Science, asked by AnushkaSharma8741, 11 months ago

A torch bulb is rated 2.5v and 750mA. Calculate 1) it's power 2) resistance 3) energy consumed,if this bulb is lighted for four hours

Answers

Answered by amitrawar1947
3
V = 2.5 V

I = 750 mA = 0.75 A

t = 4 hours = 4*3600 s = 14400 s

(a) P = VI

= 2.5*0.75

= 1.875 W

(b) R = V/I

= 2.5/0.75

= 3.33 Ω

(c) H = Pt

= 1.875*14400

= 27000 J or 27 kJ
Answered by joeljaison115
1

V = 2.5 V

I = 750 mA = 0.75 A

t = 4 hours = 4*3600 s = 14400 s

(a) P = VI

= 2.5*0.75

= 1.875 W

(b) R = V/I

= 2.5/0.75

= 3.33 Ω

(c) H = Pt

= 1.875*14400

= 27000 J or 27 kJ

Pls mark it branliest answer

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