A torch bulb is rated 2.5v and 750mA. Calculate 1) it's power 2) resistance 3) energy consumed,if this bulb is lighted for four hours
Answers
Answered by
3
V = 2.5 V
I = 750 mA = 0.75 A
t = 4 hours = 4*3600 s = 14400 s
(a) P = VI
= 2.5*0.75
= 1.875 W
(b) R = V/I
= 2.5/0.75
= 3.33 Ω
(c) H = Pt
= 1.875*14400
= 27000 J or 27 kJ
I = 750 mA = 0.75 A
t = 4 hours = 4*3600 s = 14400 s
(a) P = VI
= 2.5*0.75
= 1.875 W
(b) R = V/I
= 2.5/0.75
= 3.33 Ω
(c) H = Pt
= 1.875*14400
= 27000 J or 27 kJ
Answered by
1
V = 2.5 V
I = 750 mA = 0.75 A
t = 4 hours = 4*3600 s = 14400 s
(a) P = VI
= 2.5*0.75
= 1.875 W
(b) R = V/I
= 2.5/0.75
= 3.33 Ω
(c) H = Pt
= 1.875*14400
= 27000 J or 27 kJ
Pls mark it branliest answer
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