A torch bulb is rated 2.5V and750miliampere. Calculate it's power,it's resistance, energy consumed by bulb light for 4 hours
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Answered by
6
hello...
V = 2.5 V
I = 750 mA = 0.75 A
t = 4 hours = 4*3600 s = 14400 s
(a) P = VI
= 2.5*0.75
= 1.875 W
(b) R = V/I
= 2.5/0.75
= 3.33 Ω
(c) H = Pt
= 1.875x14400
= 27000 J or 27 kJ
thank you...
☺
V = 2.5 V
I = 750 mA = 0.75 A
t = 4 hours = 4*3600 s = 14400 s
(a) P = VI
= 2.5*0.75
= 1.875 W
(b) R = V/I
= 2.5/0.75
= 3.33 Ω
(c) H = Pt
= 1.875x14400
= 27000 J or 27 kJ
thank you...
☺
Answered by
0
a. v = 2.5v
b. i = 750ma = 0.75a
power = current × voltage
0.75 × 2.5
power = 1.875watt
b. we know that
r = v2/p
2.5 ×2.5/1.875
6.25/1.875
r= 3.33ohm
c. energy= power×time
1.875 × 14400
e= 27000J or 27KJ
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