A torch bulb is rated 2v.500mA.calculate its ,power,resistance
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Answered by
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Hi mate.
Thanks for asking this question.
Here is your answer,
Given :
(1) V =2v
(2) I = 500mA = 0.5 A
(3) P = ?
(4) R = ?
We know that,
According to the ohms law,
V = I R
putting the given values,
2 = 0.5 × R
2 / 0.5 = R
Therefore,
R = 4 ohm.
Again according to the joules law,
![p \: = {i}^{2} r p \: = {i}^{2} r](https://tex.z-dn.net/?f=p+%5C%3A++%3D++%7Bi%7D%5E%7B2%7D+r)
![p \: = {0.5}^{2} \times 4 p \: = {0.5}^{2} \times 4](https://tex.z-dn.net/?f=p+%5C%3A++%3D++%7B0.5%7D%5E%7B2%7D++%5Ctimes+4)
![p \: = 0.25 \times 4 p \: = 0.25 \times 4](https://tex.z-dn.net/?f=p+%5C%3A++%3D+0.25+%5Ctimes+4)
![p \: = 1 \: watt. p \: = 1 \: watt.](https://tex.z-dn.net/?f=p+%5C%3A++%3D+1+%5C%3A+watt.)
Thank you.
BE BRAINLY !!!!!!!!!!!!!
Thanks for asking this question.
Here is your answer,
Given :
(1) V =2v
(2) I = 500mA = 0.5 A
(3) P = ?
(4) R = ?
We know that,
According to the ohms law,
V = I R
putting the given values,
2 = 0.5 × R
2 / 0.5 = R
Therefore,
R = 4 ohm.
Again according to the joules law,
Thank you.
BE BRAINLY !!!!!!!!!!!!!
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