A torch bulb is rated 5 V and 500 mA. Calculate its Energy consumed when it is lighted for 2 and a half-hour(in KWH).
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Answer:
Given :
Potential difference =V=5V
Current =I= 500mA=500x/1000 A=0.5 A
I) Power = V X I
= 5x0.5 =5x5/10=2.5 W
II)Reistance =R=?
By Ohm's law: V=IR
R=V/I
R=5/0.5
=50/5 =10 ohms
III)Energy consumed when it is lighted for 4 hours
Energy =Power x time
t=4hrs=4x60x60
=2.5x 4x60x60
=36000joules/sec
Explanation:
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