Physics, asked by hrmnsandhu25, 4 months ago

A torch bulb is rated 5 V and 500 mA. Calculate its

(i) Power

(ii) Resistances

(iii) Energy consumed when it is lighted for 2½ hours.​

Answers

Answered by Anonymous
7

Given :Potential difference =V=5VCurrent =I= 500mA=500x/1000 A=0.5 AI) Power = V X I= 5x0.5 =5x5/10=2.5 WII)Reistance =R=?By Ohm's law: V=IRR=V/IR=5/0.5

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