Science, asked by nnv0isahansweeyasan, 1 year ago

A torch bulb is rated 5v and 500mA calculate its 1)power 2) resistance 3) energy consumed when it is lighted for 4 hours

Answers

Answered by prmkulk1978
742
Given :
Potential difference =V=5V
Current =I= 500mA=500x/1000 A=0.5 A

I) Power = V X I
= 5x0.5 =5x5/10=2.5 W

II)Reistance =R=?
By Ohm's law: V=IR
R=V/I
R=5/0.5 
=50/5 =10 ohms

III)Energy consumed when it is lighted for 4 hours
Energy =Power x time
t=4hrs=4x60x60
=2.5x 4x60x60
=36000joules/sec

Answered by Anonymous
80

Answer:

GIV€Ň :

ᴘᴏᴛᴇɴᴛɪᴀʟ ᴅɪғғᴇʀᴇɴᴄᴇ = 5ᴠ

cυrrєทτ = 500/1000 = 0.5A

1. PØŴ€Ř

P = V× I

P = 5 ×0.5

P = 2.5 W.

2.Ř€ŞIŞŦΔŇĆ€

R = V/I

R = 5/ 0.5

R = 10 ohm

3. €Ň€ŘG¥ ĆØŇŞỮΜ€Đ ŴĦ€Ň IŦ IŞ ŁIGĦŦ€Đ ₣ØŘ 4 ĦØỮŘŞ

W = P× T

W = 2.5 × 4 × 60 × 60

W = 36000 J/s.

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