Physics, asked by prajodunnimaya, 7 months ago

a torch bulb is rated 5v and 500mA. Calculate its (i) Power(II) resistance (iii) energy consumed when it is lighted for 4 hours​

Answers

Answered by saimanikantatuniki
3

Answer:

i) P = V I = 5 × 0.5 = 2.5 watt

ii) R = V / I = 5 / 0.5 10 Ω

iii) W = P × t = 2.5 × 4

Answered by atikahamedkhan70
1

Explanation:

p= VI= 5×0.5=2.5 W

R= V/I=5/0.5=10 ohm

E= p(t) =2.5(4)=10 J

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