A torch bulb is rated at 3v and 600mA.calculate its a) power,b) resistance c) energy consumed if it is used for 4 hours
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Answer:
Given that - V = 3 v
I = 600mA = 0.6 A
a) by the formula of power ,
P = V X I
P = 3 X 0.6 = 1.8 w
b) by ohms law , V = I X R
R = V / I
R = 3 / 0.6 = 5 Ohm
C ) T = 4 hrs = 4 x 60 x 60 = 14400sec
As by formula , P = E / T
E = P X T
E = 1.8 X 14400 = 25920J
E = 25.920 KJ
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