a torch is rated 2.5v,500ma. find its power and resistance
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Answer:
Explanation:
Given,
V = 2.5 V
I = 500 mA
We are given to find the power P and resistance R of the torch bulb.
So we may use the formulae,
1. P = VI
2. R = V / I
But before, have a look at the given current. It's in mA (milli Ampere). We have to convert this to Ampere.
1 mA = 1 / 1000 A
⇒ 500 mA = 500 / 1000 = 0.5 A
Hence, I = 0.5 A.
Now,
→ P = VI = 2.5 × 0.5 = 1.25 W
→ R = V / I = 2.5 / 0.5 = 5 Ω
Hence the power and resistance are 1.25 W and 5 Ω respectively
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