Question

a toroid has 3000 turns the inner and outer diameter are 22cm and 26cm calculate flux density inside the core when there is a current of 10ampere

Answer 1

Answer:

MAGNETIC FIELD IS 5mT.

Answer 2

The flux density is $5\times10^{-2}\ T$

Explanation:

Given that,

Number of turns = 3000 turns

Inner diameter = 22 cm

Outer diameter = 26 cm

Current = 10 A

We need to calculate the flux density

Using formula of flux density

$B=\dfrac{\mu n\times i}{l}$

$B=\dfrac{2\mu N\times i}{2\pi(r_{1}+r_{2})}$

Put the value into the formula

$B=\dfrac{2\times4\pi\times10^{-7}\times3000\times10}{2\pi(11\times10^{-2}+13\times10^{-2})}$

$B=0.05\ T$

$B=5\times10^{-2}\ T$

Hence, The flux density is $5\times10^{-2}\ T$

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Topic : flux density

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