Question

A toroid of 6cm diameter possess 50 turns per cm. A current of 2A is flowing through it. The magnetic induction inside the toroid is​

Answer 1

Answer:

good guy ifogdifofodkfkfkczb

Answer 2

Answer:

9.46*10^(-6)T.

Explanation:

The turns for the coil per area of the coil will be given as n=N/2πr where N is the number of turns of the solenoid and the r is the radius of the solenoid. So, n=50/2*3.14*0.6 which on solving we will get n=3.768.

So, the magnetic field will be given by the formulae of B=uni where i is the current through the coil and u is the permeabilty so the B=4πx10^(-7)x3.768x2 which on solving we will get the value of magnetic field as 9.46*10^(-6)T.