Question

A toroidal coil is wound on a ring made of a good grade of iron for which, applied magnetic

field is 12x103 A/m and magnetic induction or magnetic flux density is 1.8 Tesla. Calculate

magnetic permeability of medium, magnetic susceptibility and intensity of magnetization​

Answer 1

Given:

Magnetic field strength(H):12×$10^{3}$ A/m

Magnetic flux density(B):  1.8 Tesla

To find:-

1. What is the magnetic permeability of the medium.
2. What is the magnetic susceptibility.
3. What is the intensity of magnetization.

Solution:

1. Magnetic permeability(∪)= $\frac{B}{H}$ = $\frac{1.8 T}{12000 A/m}$ =$1.8$÷$10^{3}$ = $0.00015$ =$1.5$×$10^{-4} }$
2.   For magnetic susceptibility(X) we have to find relative permeability                    first  for that we have $Uo=4\pi$×, $B$$=1.8 T$and$H=12$×$10^{3}$                              : ∪r=$\frac{B}{(Uo )H}$ =$1.8$÷($4\pi$×$10^{-7}$×$12$×$10^{3}$) = $120$.                                                                               then, therefore,  Magnetic susceptibility(X)=∪r-1=$120-1$=$119$.
3. Intensity of magnetization(I) : By the analysis of Magnetic permeability (∪) and Magnetic susceptibility(X) the Intensity of Magnetization will be                                                                                 $I$  = $\frac{B}{Uo}$=$1.8$÷$4\pi$×$10^{-7}$=$1433121.019$ $Am^{-1}$ .