Question

a torque of 100 nm is applied to a body, capable of rotating about a given axis. if the body starts from rest and acquires kinetic energy of 10,000 j in 10 second, find (a) its moment of inertia about given axis, (b) angular momentum at the end of 10 second.

Answer 1

Answer:

Given ω=1rpm

Angular momentum =0.24πkgm

2

/s

Now, w

=1rpm

=1×

60

2π

rad /S

Rotational Kinetic energy

=

2

1

×Iω

2

=

2

1

×(Iω)×ω

=

2

1

×L×ω

=

x

1

×0.24π×

60

2π

=0.004π

2

J

15 seconds

1 seconds