a torque of 10Nm produces an angular acceleration of 4rad/ s^2 for a uniform circular disc . what is the moment of inertia of the disc about the axis of rotation.
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Answer: 2.5 kg m^2
Explanation: Torque = Momentum of inertia X Angular Acceleration
T=Iα
10NM= I X 4 rad/s^2
I = 10/4
I = 2.5 kg m^2
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