Physics, asked by ironman70280, 6 months ago

A torque of 2 × 10-4 N-m is required to hold a
magnet at right angles to the magnetic
meridian. The torque required to hold it at 30°
to the magnetic meridian in N-m is
a) 0.5 x 10-4
b) 1 x 10-4
c) 4 x 10-4
d) 8 x 104​

Answers

Answered by venkatasaikumar75
0

Answer:

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Explanation:

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