Question

A torque of 4000nm acting on a body of mass 80kg produced an angular acceleration of 20rad/s² calculate the moment of inertia of the body.​

Answer 1

◆ Answer:—

• I = 20 kgm²
• R = 0.707 m

◆ Explanation:—

Given :—

• α = 20 rad/s²
• τ = 400 Nm
• m = 40 kg

Solution:—

Moment of inertia is calculated as -

• → I = τ / α
• → I = 400 / 20
• → I = 20 kgm²

Radius of gyration is calculated as -

• → R = √(I / m)
• → R = √(20 / 40)
• → R = √(1/2)
• → R = 0.707 m