Question

A torque of 5 Nm is applied on a particle for 2 seconds, calculate the change in its angular
momentum.​

Answer 1

Answer:

10Nms

Explanation:

momentum is equal to mass(m) *velocity

force is mass *velocity/time

thus momentum is force * time

let initial velocity(u) be 0

mv-mu is 5*2

since mu is 0,rate of change of momentum is 10Nms

Answer 2

Answer:change in angular momentum or dl=10

Explanation: since we know that dl/dt= T

Therefore, dl=dt * T

=> dl= 5*2=10