Question

A torque of 600N m acting on a body of mass 40 kg produces an angluar acceleration of 20rad/s²calculat the momemt of inertia of the body​

Answer 1

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Answer 2

◆ Answer -

I = 20 kgm^2

R = 0.707 m

◆ Explanation

-

# Given -

α = 20 rad/s^2

τ = 400 Nm

m = 40 kg

# Solution -

Moment of inertia is calculated as -

I = τ / α

I = 400 / 20

I = 20 kgm^2

Radius of gyration is calculated as -

R = √(I / m)

R = √(20 / 40)

R = √(1/2)

R = 0.707 m

Hope this helps you.