A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s. If the tortoise walks the first part and crawls the second, it takes 110seconds. If it crawls the first part and walks the second, it takes 100 seconds. Find the lengths of the parts of the journey.
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Solution:
Let x cm - walk
Let y cm - crawl
x/4 + y/3 = 110
3x+4y /12= 110
3x+4y = 1320... Eq.1
x/3 + y/4 = 100
4x+3y / 12 = 100
4x+3y = 1200...Eq.2
Let multiply equation 1 by -4
Let multiply equation 2 by 3
-12x-16y= -5280
12x+9y = 3600
Add the two equations
-7y = -5280+3600
-7y = -1680
y = -1680/-7
y = 240 cm crawl
Substitute the value of y in equation 1
3x+4y=12*110
3x+960=1320
3x=1320-960
3x=360
x = 120 cm walking
Hope this would help
Let x cm - walk
Let y cm - crawl
x/4 + y/3 = 110
3x+4y /12= 110
3x+4y = 1320... Eq.1
x/3 + y/4 = 100
4x+3y / 12 = 100
4x+3y = 1200...Eq.2
Let multiply equation 1 by -4
Let multiply equation 2 by 3
-12x-16y= -5280
12x+9y = 3600
Add the two equations
-7y = -5280+3600
-7y = -1680
y = -1680/-7
y = 240 cm crawl
Substitute the value of y in equation 1
3x+4y=12*110
3x+960=1320
3x=1320-960
3x=360
x = 120 cm walking
Hope this would help
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