Question

A total charge of 4 * 10^-6 C is distributed uniformly on the surface of a thin-walled hemispherical cup of radius 10 cm. Calculate the electric field strength at the centre of hemisphere.​

Answer 1

Answer:

total charge of

5

μ

c

is distributed uniformally on the surface of the thin walled semi spherical cup. If the electric field strength at the center of the semi sphere is

9

×

10

8

N

C

−

1

, the radius of the cup is:

(

1

4

π

∈

0

=

9

×

10

9

N

m

2

C

−

2

)

A5 mm

B10 mm

C5 cm

D10 cm

Solution

Electric field at the center of a semispherical cup of surface charge density

σ

=

σ

4

ϵ

0

=

9

×

10

8

⟹

σ

=

4

ϵ

0

×

9

×

10

8

=

1

10

π

⟹

q

2

π

R

2

=

1

10

π

Explanation:

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