Physics, asked by sheelaharani, 3 months ago

A total charge of 6.3×10−8 C is distributed uniformly throughout a 2.7-cm radius sphere. The

volume charge density is

Answers

Answered by ansari266272
1

Explanation:

volume of sphere

v =  \frac{4 }{3}  \: \pi \: {r}^{2}

Attachments:
Answered by harisreeps
1

Answer:

A total charge of 6.3×10−8 C is distributed uniformly throughout a 2.7cm radius sphere. The  volume charge density is 0.79*10^{-3}  C/m^{3}

Explanation:

  • The volume charge density (ρ) is the charge (q) in unit volume (v), that is

        ρ= q/v

  • For a sphere of radius (r) volume is given by v=\frac{4}{3} \pi r^{3}

From the question, we have

the total charge present q=6.3*10^{-8}C

the radius of the sphere r=2.7cm=0.027m

the volume of the sphere v=\frac{4}{3}* \pi* 0.027^{3}=7.9*10^{-5}m^{3}

the volume charge density is

ρ= \frac{6.3*10^{-8} }{7.9*10^{-5} } =0.79*10^{-3}  C/m^{3}

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