a total charge of q coul is uniformly distributed along a rod 40 cm in length. find the electric field intersity 20 cm away from the rod along it's perpendicular bisector
Answers
Answered by
1
Answer:
Total charge =Q
Straight rod of length =L
distance from P is h midpoint of the rod
∫
x
2
+a
2
dx
=ln(x+
x
2
+a
2
)
V=
4πϵ
0
1
L
Q
∫
x
2
+a
2
dx
(due to the perpendicular to the value of x)
when x=L and a=
3
h
=
4πϵ
0
1
L
Q
ln(x+
x
2
+a
2
)
=
4πϵ
0
1
L
Q
ln(x+
L
2
+(
3
h)
2
)
=
4πϵ
0
1
×
L
Q
ln(L+
L
2
+3h
2
)
Similar questions