A total of 40 apples are distributed among A, B, C, D, E AND F. The no. of apples with A, B, C, D, E AND F are in decreasing order. The no. of apples with B is twice that with D. The no. of apples with C is thrice that with E. The difference in the no. of apples with A and B is same as that with E and F. 4. What is the no. of apples with E?
Answers
Given : A total of 40 apples are distributed among A, B, C, D, E AND F. The no. of apples with B is twice that with D. The no. of apples with C is thrice that with E. The difference in the no. of apples with A and B is same as that with E and F
To find : no. of apples with E
Solution:
A + B + C + D + E + F = 40
B = 2D
C = 3E ( C can be 6 or 9 as if C = 12 then B , A minimum 13 & 14 and E =3 and sum will be more than 40 . if C = 3 then E = 1 but E > F hence can not be 1 )
A - B = E - F
so We will take Case 1
C = 6
=> E = 2
F can be only 1
D can be maximum = 5
=> B Can be maximum = 10
& A can be Maximum = 11
Maximum Sum = 11 +10 + 6 + 5 + 2 + 1 = 35 < 40
Hence C can not be 6
so we lft with only Case 2
C = 9
E = 3 ( we got our solution here)
lets verify if there exist a possible condition or not
F can be 1 or 2
D minimum can be 5
B can be 10
A can be 11 or 12
if D > 5 then sum will exceed 40
Two possible solution
A = 11 , B = 10 C = 9 D= 5 E = 3 F =2
A = 12 , B = 10 C = 9 D = 5 E = 3 F = 1
in both cases E = 3
no. of apples with E = 3
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