Question

a total of 500 people took dips in a rectangular tank which is 80 metre long and 50 metre board what is the total rise in the level of water in the tank if the average volume of water that is displaced power(or raised) raised by one person in 0.04 mcube?​

Answer 1

I don’t know how to do this please get help from your teacher

Answer 2

$\textbf{\huge\underline{\underline\red{solution} : - }} \\ \\ \bold{\underline\purple{here \: we \: know}} \\ \\ \red{1.} \bold \blue{ \: length \: (l)\: of \: cuboidal \: \: tank \: is \: 80 \: m .} \\ \red{2.} \bold \blue{ \: breadth \:( b)\: of \: cuboidal \: tank \: is \: 50 \: m.} \\ \red{3.} \bold \blue{ \: displacement \: of \: water \: by \: a \: one \: } \\ \bold \blue{person \: in \: a \: tank \: is \:0.04 \: {m}^{3} .} \\ \\ \underline \bold\red{so \: \:displacement \: of \: water \: in \: a \: tank \: by \:} \\ \underline \bold\red{ 500 \: persons } = \blue{500 \times0.04 = 20\: }\bold\blue{ {m}^{3} \: \: \: \: ..(1)} \\ \\ \underline \bold \purple{let \: height \: of \: cuboidal \: tank \: is \: h} \\ \\ \underline\bold\blue{to \: find \: volume \: of \: water \: in \: tank} \\ \\ \underline \bold \red{volume\: of \: cuboidal \: tank \: } = \bold \purple{ l\times b\times h} \\ \\ \bold \red{v.o.c.t} = \bold \purple{80 \times 50 \times h} \\ \\ \bold \red{v.o.c.t} = \bold \purple{(4000 \times h \: \: ) {m}^{3} \: \: \: ..(2) } \\ \\ \underline\bold\blue{as \: we\: know} \\ \\ \underline\bold\purple{volume \: of \: raised \: water \: in \: cuboidal } \\ \underline\bold\purple{tank \: is \: equal \: to \: displacement \: of \: water \: in } \\ \underline\bold\purple{ tank\: by \:500 \: person .} \\ \\ \underline\bold\red{hence} \\ \\ \bold\red{volume \: of \: raised \: water \: in \: cuboidal} \\\bold\red{tank \:} = \bold\purple{ displacement \: of \: water \: in } \\ \bold\purple{ tank\: by \:500 \: person .} \\ \\ = > \bold \blue{4000 \times h} = \bold \blue{20} \\ \\ = > \bold \blue{h} = \bold \blue{ \frac{20}{4000}} = \bold \blue{ \frac{1}{200} } = \bold \blue{0.005 \: m} \\ \\ \underline \bold\red{Hence \: \purple{0.005 \: m} \: level \: of \: water \: rise \: in \: tank.}$