Question

A total of 6×10^46 is flows through a current carrying conducter when connected through an external power supply for 20 sec find the value of current in the conductor​

Answer 1

Given that:

• A total of 6 × 10⁴⁶ electrons flows through a current carrying conducter when connected through an external power supply for 20 seconds.

To Find:

• The value of current in the conductor.

We know that:

• I = ne/t

Where,

• I = Current
• n = Number of electrons
• e = Electron
• t = Time

We have:

• n = 6 × 10⁴⁶
• e = 1.6 × 10⁻¹⁹ C
• t = 20 s

Finding the value of current:

↠ I = (6 × 10⁴⁶ × 1.6 × 10⁻¹⁹)/20

↠ I = 4.8 × 10²⁶

Hence,

• The value of current in the conductor is 4.8 × 10²⁶ Ampere.

Answer 2

Answer :-

Given :-

› Total number of electrons (n) = 6 × 10⁴⁶ electrons.

› Time taken (t) = 20 seconds.

To find :-

› Electric current in the conductor (I).

Solution :-

• q = ne - (i)

Principal of quantisation of electric charge:

• I = q/t
• I = ne/t (from i)

Where,

› I = Electric current.

› n = Total number of electrons.

› e = Electron chare.

› t = Time taken.

Substituting we get,

› I = (6 × 10⁴⁶ × 1.6 × 10⁻¹⁹ C)/20 s

› I = (9.6 × 10⁴⁶ × 10⁻¹⁹ C)/20 s

› I = (9.6 × 10²⁷ C)/20 s

› I = 0.48 × 10²⁷ C

› I = 4.8 × 10²⁶ Ampere.

∴ The value of the current in the conductor is 4.8 × 10²⁶ A.