Question

A total of 6×10^46 is flows through a current carrying conducter when connected through an external power supply for 20 sec find the value of current in the conductor .​

Answer 1

Answer:

4.8 x 10^26 Volt

Explanation:

Given,

n=6x10^46

t=20 seconds

e=1.6 x 10^-19 Coulomb

To find,

Current (I)

Solution :

I = (n x e)/t

I = (6 x 10^46 x 1.6 x 10^-19)/20

I = (9.6 x 10^(46-19))/20

I = (9.6 x 10^27)/20

I = (960 x 10^25)/20

I = 48 x 10^25

Therefore,

I = 4.8 x 10^26 Volt

Note :

10^26 means 10 raised to 26 or 10 to the power 26

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Step-by-step explanation: