A total of 6x10^46 electrons flow through a current carrying conductor when connected through an external power supply for 20 seconds. Find the value of the current in the conductor.
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Answer:
I = 4.8*10^36 ampere
Explanation:
no. of electron,n = 6 *10^46
charge of an electron,e = 1.6*10^-19 c
time, t = 20 second
charge on conductor , Q = n*e
Q = 6 *10^46 * 1.6*10^-19
Q = 9.6 * 10^(46-19)
Q = 9.6 * 10^37 c
current on coductor , I = Q/t
I = 9.6 *10^37/20 = 4.8*10^36 ampere