Question

A tourist bus left town A and travelled at an average speed of 85 km/hr to town B which was 340 km away. If it reached town B at 1:15 pm, at what time did it start?

Answer 1

Average speed = 85 kmph
Distance from town a to b = 340 km
Time it reached at town B = 1:15 pm
So time taken = 340/85 hr = 4 hrs
Therefore starting time = 13:15-4:00hrs = 9:15 am
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Answer 2

Answer:

91:5 a.m.

Step-by-step explanation:

Given,

• A tourist bus left town A.
• It travelled at an average speed of 85 km/hr to town B.
• Town B was 340 km away.
• The bus reached town B at 1:15 p.m.

To Find: The time at which the Bus started from town A

Explanation:

• To solve this question we need to know about the basic relationship between Distance, Average Velocity and Time.
• basic relationship between Distance, Average Velocity and Time.(Distance/Time) = Average Velocity
• Here, we will have to calculate the Time taken, and then subtract it from 1:15 p.m.
• $\frac{340}{85} = 4$
• That is, the bus has taken 4hours to reach from town A to town B.
• As it reached town B at 1:15p.m., then it started from town A 4 hours before 1:15 p.m. which is 9:15 a.m.

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