Question

A tourist covers half of his journey by train at 60 km/h, half of the remainder by bus at 30 km/h and the rest by cycle at 10 km/h. the average speed of the tourist in km/h during his entire journey is

Answer 1

average speed=total/No of 60+30+10+1/4=101/4

Answer 2

Answer:

Step-by-step explanation:

LCM of 60km,30km,10km=60km

Hence the total distance=60km

Average speed=Total distance/total time

Half of the journey covered by train at a speed of 60km/h

i.e=half of distance/speed=30/60=1/2h

remaining half of the journey covered by bus at a speed of 30km/h

i.e=remaining half of distance/speed=15/30=1/2h

rest distance=60-(30+15)=15

i.e=15/10=3/2

total time taken to complete the journey=1/2+1/2+3/2=5/2

Average speed=Total distance/Total time=60/5/2=24km/h   (ans)

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