Question

A Towel in the shape of isosceles trapezium whose parallel sides are 14cm and 12cm, the
distance between them is 6cm. Find the area of the Towel​

Answer 1

Answer:

Area of trapezium=  

2

1

​  

×Sum of parallel sides×Distance between them.

Area of trapezium =  

2

h

​  

(a+b), where a and b are base and h is height.

Here, a=24 cm, b=20 cm and h=15 cm

Therefore, Area=  

2

15

​  

(24+20)=330cm  

2

Step-by-step explanation:

Answer 2

$\bf \: \underline{Given} :$ ↴

$\sf \implies A \: towel \: is \: in \: the \: shape \: of \: an \: isosceles \: trapezium.$

$\sf \implies The \: parallel \: sides \: of \:the\: towel \: are \: 14 \: cm \: and \: 12 \: cm.$

$\sf \implies The \: distance \: between \: the \: parallel \: sides \: is \: 6 \: cm.$

$\bf \: \underline{To \: find} :$ ↴

$\sf \implies Area \: of \: towel$

$\bf \: \underline{Formula \: to \: be \: used},$

$\sf \implies \underline{ \boxed{ \pink{\sf Area \: of \: trapezium = \dfrac{1}{2} \times (P_1 \times P_2) \times D}}}$

$\sf \: Where,$

$\sf \implies P_1 = Length \: of \: first \: parallel \: side$

$\sf \implies P_2 = Length \: of \: second \: parallel \: side$

$\sf \implies D = Distance \: between \: parallel \: sides$

$\bf \: \underline{\underline{Solution}}$

$\sf \implies \sf \dfrac{1}{2} \times (14 \times 12) \times 6$

$\sf \implies \sf \dfrac{1}{2} \times (26) \times 6$

$\sf \implies \sf \dfrac{1}{2} \times 26 \times 6$

$\sf \implies \sf \dfrac{1}{2} \times 156$

$\sf \implies \sf \dfrac{156}{2}$

$\sf \implies \sf 78$

$\underline{ \boxed{ \pink{\sf \: Hence, area \: of \: towel = 78 \: cm ^{2}}}}$