Question

A towel in the shape of isoscsles trapezium whose parallel sides are 14cm and 12cmthe distance between them is 6cmFind the area of the towel​

Answer 1

Answer:

area of trapezium= ½×h×(a+b)

½×6×(14+12) cancellation

1×3×(26) = 78

so the area of the trapezium shaped towel is 78 sq.units

Answer 2

Answer:

• Area of the towel is 78 cm².

Step-by-step explanation:

Given that:

• A towel is in the shape of an isosceles trapezium whose parallel sides are 14 cm and 12 cm.
• The distance between the parallel sides are 6 cm.  

To Find:

• Area of the towel.

As we know that:

• Area of trapezium is :

$\sf{\left\{\dfrac{1}{2}\times(P_1+P_2)\times D\right\}\;sq.\;units}$

Where,

• P₁ = Length of 1st parallel side
• P₂ = Length of 2nd parallel side  
• D = Distance between the parallel sides

Substituting the values,

$\sf{\longmapsto\left\{\dfrac{1}{2}\times(14+12)\times 6\right\}\;cm^2}$

Solving the bracket,

$\sf{\longmapsto\left\{\dfrac{1}{2}\times(26)\times 6\right\}\;cm^2}$

Opening the bracket,

$\sf{\longmapsto\left\{\dfrac{1}{2}\times26\times 6\right\}\;cm^2}$

Reducing the numbers,

$\sf{\longmapsto\left\{\dfrac{1}{1}\times13\times 6\right\}\;cm^2}$

$\sf{\longmapsto\left\{13\times 6\right\}\;cm^2}$

Multiplying the numbers,

$\sf{\longmapsto78\;cm^2}$

Hence, area of the towel is 78 cm².