Question

A tower 30 m high, casts a shadow 30 m long on the ground, then what is the angle of

elevation θ of the sun? ( 0° ≤ θ ≤ 90°)​

Answer 1

Answer:

sorry for interrupting

but thanks for free points

Answer 2

Answer:

Angle of elevation = 45°

Step-by-step explanation:

height of tower = QS = 30m

Length of shadow = PQ = 30m

Angle of elevation = θ

tan θ = $\frac{QS}{PQ}$

tan θ  = 30/30 = 1

tan θ = 1

tan 45° = 1

∴θ = 45°

Angle of elevation = 45°