A tower AB is 20 m gh and BC , its shadow on ground , is 20âà ö3 m long. Find the sun 's altitude.
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Ab/ Bc = 20/ 20√3
Ab/ Bc = 1/√3
Ab/ Bc = Perpendicular/ Base
tan theta = 1/√3
theta = 30°
therefore, Sun's altitude = 30°
Ab/ Bc = 1/√3
Ab/ Bc = Perpendicular/ Base
tan theta = 1/√3
theta = 30°
therefore, Sun's altitude = 30°
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