Question

A tower AB is 20 m high and BC , its shadow on ground , is 2√3 m long. Find the sun 's altitude.

Answer 1

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Here's ur answer :-


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=) From the figure ,


=) Height of the tower = AB = 20 m


=) Length of the shadow = BC = 20√3 m


=) the altitude of the Sun = <ACB


=) tan <ACB = AB/CB


=) 20/20√3


=) 1/√3


=) tan <ACB = tan 30°


=) <ACB = 30°


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