Question

A tower AB is 20 m high and BC , its shadow on ground , is 20√3 m long. Find the sun 's altitude.

Answer 1

From the figure ,

Height of the tower = AB = 20 m

Length of the shadow = BC = 20√3 m

the altitude of the Sun = <ACB

tan <ACB = AB/CB

= 20/20√3

= 1/√3

tan <ACB = tan 30°

<ACB = 30°

I hope this helps you.

: )

Answer 2

Given that AB = height = 20 m 

BC  = base = 20√3 m

=======================

tan Ф = $\frac{20}{20 \sqrt{3} }$

tan Ф = $\frac{1}{ \sqrt{3} }$

tan Ф = tan 30 

Ф = 30 


Sun's altitude is at  30°





i hope this will help you

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