A tower AB is 20 m high and BC , its shadow on the ground , is 60 m long. Find the sun's altitude
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Area of triangle=1/2×base×height
=1/2×60×20
=30×20
=1200m^2
=1/2×60×20
=30×20
=1200m^2
NakulBaadshah:
wrong
by Pythagoras theorem,AC=40m.
therefore sin C=AB/BC=20/40=1/2=sin 30.
therefore angle is 30 degree
please take the last 3 messages into concern..
is it correct or wrong?
it is correct i know
by Pythagoras , AC=10√26
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