A tower AB is 20m high and BC,its shadow on the ground,is 20 root 3 long find the sun's altitude
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The figure of the given situation is attached. Let the blue line AB represent thd tower which is 20 m high and BC represent the shadow of the tower which 20√3 m long.
As said in the problem, we need to find the altitude of the sun. By altitude, we mean the angle formed by the sun that is <ACB.
This problem can be solved by using Trigonometric Ratios, particularly, Tangent.
So,
We know that
tanθ = perpendicular / base
tanθ = AB / BC
tanθ = 20 / 20√3
tanθ = 1 / √3
Now, we know that the value of tanθ comes 1/√3 when θ = 30°.
<ACB = 30°
Thus, the sun's altitude is 30°.
♥️♥️
As said in the problem, we need to find the altitude of the sun. By altitude, we mean the angle formed by the sun that is <ACB.
This problem can be solved by using Trigonometric Ratios, particularly, Tangent.
So,
We know that
tanθ = perpendicular / base
tanθ = AB / BC
tanθ = 20 / 20√3
tanθ = 1 / √3
Now, we know that the value of tanθ comes 1/√3 when θ = 30°.
<ACB = 30°
Thus, the sun's altitude is 30°.
♥️♥️
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