A tower and a pole stand vertically on the same level groundb.it is observed that tha angles of depression of top and foot of the pole from the top of the tower of height 60m is 30 and 60 degree. Find the height of the pole.
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A tower and a pole stand vertically on the same level ground. It is observed that the angles of depression of top and foot of the pole from the top of the tower of height 60 m is 30° and 60° respectively
To find : height of the pole,
Solution:
Angle of Elevation = Angle of Depression
Tan60° = AB/BD
=> √3 = 60/BD
=> BD = 60/√3
=> BD = 20√3
Tan30° = AE/EC
EC = BD = 20√3
=> 1/√3 = AE/20√3
=> AE = 20
AE = AB - CD
=> 20 = 60 - h
=> h = 40
Height of Pole is 40 m
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