Question

a tower Casts a shadow of length 100m at a time when 12 m high pole casts a Shadow of length 16 m find the height of the tower

Answer 1

its a question of triangle

In ∆ABC and ∆PQC
angle C = angle C (common)
angle B = angle Q {each 90°( sorry I didn't
mentioned)}
so, ∆ABC ~ ∆PQC( by AA similarity)
hence, AB / PQ = BC / QC
AB / 12 = 100 / 16

so, AB = 75m

Answer 2

A 12m pole casts shadow of=16m

A 100m pole casts shadow

 =(12÷16)x100

= 0.75 x 100

  = 75m

Step-by-step explanation: