a tower Casts a shadow of length 100m at a time when 12 m high pole casts a Shadow of length 16 m find the height of the tower
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its a question of triangle
In ∆ABC and ∆PQC
angle C = angle C (common)
angle B = angle Q {each 90°( sorry I didn't
mentioned)}
so, ∆ABC ~ ∆PQC( by AA similarity)
hence, AB / PQ = BC / QC
AB / 12 = 100 / 16
so, AB = 75m
In ∆ABC and ∆PQC
angle C = angle C (common)
angle B = angle Q {each 90°( sorry I didn't
mentioned)}
so, ∆ABC ~ ∆PQC( by AA similarity)
hence, AB / PQ = BC / QC
AB / 12 = 100 / 16
so, AB = 75m
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2
A 12m pole casts shadow of=16m
A 100m pole casts shadow
=(12÷16)x100
= 0.75 x 100
= 75m
Step-by-step explanation:
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