Question

A tower is 100 metres high. Find the angle of elevation of its top from a point 100√3 metres away from its foot.​

Answer 1

Answer:

The Correct Answer is 30 Degrees

Step-by-step explanation:

Let the angle of elevation be:

Height of tower = 100m

(Base) Distance from a point to the base of tower = 100$\sqrt{3}$ m

Let the angle of elevation be $\alpha$

Therefore,

tan$\alpha = \frac{Height}{Base}$

$tan\alpha = \frac{100}{100\sqrt{3} }$

$\alpha = tan^{-1}\frac{1}{\sqrt{3} }$

$\alpha = 30 Degrees$