A tower is 5 root 3 meters height. find the angle of elevation of its top from a point 5meter away from its foot
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anushkhan:
what is this
how can a tower be 5 root
5root3meters height
okay u mean root5
??????
no
first 5 then root 3
OKAY
since perpendicular=5 root 3 meters
base=5 meters
Therefore, tan thita=p/b
=5 root 3/5
tan thita=root 3
tan thita=tan 60° (tan 60°=root 3)
thita=60°
therefore, the angle of elevation is 60°
base=5 meters
Therefore, tan thita=p/b
=5 root 3/5
tan thita=root 3
tan thita=tan 60° (tan 60°=root 3)
thita=60°
therefore, the angle of elevation is 60°
he is saying to find the angle of elevation
Answered by
6
since perpendicular=5 root 3 meters
base=5 meters
Therefore, tan thita=p/b
=5 root 3/5
tan thita=root 3
tan thita=tan 60° (tan 60°=root 3)
thita=60°
therefore, the angle of elevation is 60°
HOPE THIS HELPS YOU!!
PLEASE MARK IT AS BRAINLIEST!!
base=5 meters
Therefore, tan thita=p/b
=5 root 3/5
tan thita=root 3
tan thita=tan 60° (tan 60°=root 3)
thita=60°
therefore, the angle of elevation is 60°
HOPE THIS HELPS YOU!!
PLEASE MARK IT AS BRAINLIEST!!
plz can u answer this on paper
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