A Tower is 50m high when the sun altitude is 45 degrees then what will be the length of its shadow.
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tan theta = p/q
tan 45° = p/50
1 = p/50
so ,p = 50
hence,shadow will be of same length.
tan 45° = p/50
1 = p/50
so ,p = 50
hence,shadow will be of same length.
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answer of kaur question
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