a tower is100√3 mitre high. find the angles of evalution of its top from a points100 mitres away from its foot
Answers
Answered by
1
Step-by-step explanation:
100√3/100
=√3
=TAN 60
ANGLE OF ELEVATION IS 60
Answered by
0
Answer:
60°
Step-by-step explanation:
The dist. from tower to the pt. = 100 m, and the height of tower is C m.
Hence, we can consider it as a right triangle, whose p is 100√3 m (height of tower) and b = 100 m. (dist. of pt. from tower)
As the angle of elevation is the base angle, we can consider it as x
So, tanx = height of tower/dist. of pt. from tower
= 100√3/ 100 = √3 = tan60°
Hence x = 60°, which is the angle of elevation.
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