Question

A tower of height 100 m casts a shadow
of length 100root3 m then what is the
angle of elevation of the sun at that
time?​

Answer 1

Answer:

30°

Step-by-step explanation:

Height is 100m

Length of shadow 100√3

I am attaching a diagram of question.

Tan A = Perpendicular/ Base

Tan A = 100/ 100√3

Tan A = 1/√3

Tan A = Tan 30°

A = 30°

Answer 2

Answer:

Height=100

length of shadow=100√3

tan A=100/100√3

=1/√3

tan A=30°

A=30°

therefore the angle of elevation of the sun at the time is 30°

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