a tower of height 30m casts a shadow of 10root3 then find the angle of elevation of it?
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h= 30m.
B= 10√3.
tan theta = h /B.
tan theta = 30 / 10√3.
tan theta =√3.
theta = 60°.
therefore, angle of elevation = 60°.
mark it BRAINLIEST plzz..
B= 10√3.
tan theta = h /B.
tan theta = 30 / 10√3.
tan theta =√3.
theta = 60°.
therefore, angle of elevation = 60°.
mark it BRAINLIEST plzz..
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