Question

a tower of height hstands on the horizontal ground and a particle projected with speed u from the top so as to hit the ground at the greatest distance from the foot of the tower.prove that distance is u/g under root u²+2gh​

Answer 1

Answer:

ANSWER

Given Horizontal velocity =V

H

=

2gh

,

Vertical velocity=V

V

=0

Using s=ut+

2

1

at

2

⇒−h=0−

2

1

gt

2

⇒t=

g

2h

∴ x=V

H

×t ⇒x=

2gh

×

g

2h

=2h

Explanation:

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