Question

A tower stand vertically on the ground from a point on the ground and M away from the foot of the tower the angle of elevation of the top of the tower is 45 degree find the height of the tower

Answer 1

Let AB is the height of the tower.

Now in triangle ABC

tan 45° = AB/BC

=> 1 = AB/15   (BC =15 and tan 45° = 1)

=> AB = 15

So height of the tower = 15 m