A tower stand vertically on the ground from a point on the ground which is 30 m away from the foot of a tower the angle of elevation of the top of tower is found to be 45 degree find the height of the tower
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30m away / 45
∘
inclination.
Let the height of tower be h m
so AB=hm
Distance of the point from
foot of tower = 30m
CB=30m
Angle of elevation =45
∘
∠ACB=45
∘
Since tower is vertical to ground
∠ABC=90
∘
Now tanC=
sideadjacenttoangleC
sideopptoangleC
tanC=
CB
AB
tan45=
CB
AB
1=
30
H
H=30
Hence height of tower = 30m
Answer = option C=30m
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