A tower stands at the center of a circular park. A and B are two points on the boundary of the park such that AB(=a) subtends an angle of 60 degrees at the foot of the tower, and the angle of elevation of the top of tower from A or B is 30degrees. The height of the tower is?
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Answer:A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB(=a) subtends an angle of 60∘ at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30∘ . The height of the tower is (1) 2a√3 (2) 2a√3 (3) a√3 (4) a√3.
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Imagine the figure as 3D image
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