Question

A tower stands on a horizontal plane. P is the top and Q is the foot of the tower.A and B are two points on this plane such that AB is 32m and QAB is a right angle. It is found that cot angle PAQ = 2÷5 and cot angle PBQ = 3÷5.Find the height of the tower.

Answer 1

horizontal plane is the top and she is the foot of the tower and b are two points on this plane such that a b is 32 and a b is a right triangle triangle if it is found that kot angle p 22 divided by 5 and kot angle ptq 3 divided by 5 find the height of the tower Pythagoras theorem cynical sector 82 easy question you should do it yourself solution has not ask this something really Francis only talk questions not this much easy questions